Raspberry Pi 樹莓派 USB Barcode 掃瞄並讀取 QRCode for Python3
所需設備
- Raspberry Pi 樹莓派並安裝好官方系統。
- USB Barcode 手持掃瞄器。
查看 USB 裝置
查看 USB 裝置:
lsusb
Bus 002 Device 001: ID 1d6b:0003 Linux Foundation 3.0 root hub
Bus 001 Device 003: ID 1fc9:5aa7 NXP Semiconductors WCM Keyboard
Bus 001 Device 002: ID 2109:3431 VIA Labs, Inc. Hub
Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub
查看裝置名稱 (最後的數字會隨插入優先序流水號遞增)
sudo ls -a /dev | grep hidraw*
hidraw0
掃瞄後讀取資訊
新增檔案 usb-barcode-scanner.py,撰寫程式碼:
#!/usr/bin/python
import sys
def barcode_reader():
hid = {4: 'a', 5: 'b', 6: 'c', 7: 'd', 8: 'e', 9: 'f', 10: 'g', 11: 'h', 12: 'i', 13: 'j', 14: 'k', 15: 'l', 16: 'm',
17: 'n', 18: 'o', 19: 'p', 20: 'q', 21: 'r', 22: 's', 23: 't', 24: 'u', 25: 'v', 26: 'w', 27: 'x', 28: 'y',
29: 'z', 30: '1', 31: '2', 32: '3', 33: '4', 34: '5', 35: '6', 36: '7', 37: '8', 38: '9', 39: '0', 44: ' ',
45: '-', 46: '=', 47: '[', 48: ']', 49: '\\', 51: ';', 52: '\'', 53: '~', 54: ',', 55: '.', 56: '/'}
hid2 = {4: 'A', 5: 'B', 6: 'C', 7: 'D', 8: 'E', 9: 'F', 10: 'G', 11: 'H', 12: 'I', 13: 'J', 14: 'K', 15: 'L', 16: 'M',
17: 'N', 18: 'O', 19: 'P', 20: 'Q', 21: 'R', 22: 'S', 23: 'T', 24: 'U', 25: 'V', 26: 'W', 27: 'X', 28: 'Y',
29: 'Z', 30: '!', 31: '@', 32: '#', 33: '$', 34: '%', 35: '^', 36: '&', 37: '*', 38: '(', 39: ')', 44: ' ',
45: '_', 46: '+', 47: '{', 48: '}', 49: '|', 51: ':', 52: '"', 53: '~', 54: '<', 55: '>', 56: '?'}
# 第一個參數:掃瞄器裝置,第 2 個參數:r 讀取、b 二進位
fp = open('/dev/hidraw0', 'rb') #Just have a look there if you can see something
str = ""
shift = False
done = False
while not done:
# Get the character from the HID
buffer = fp.read(8) # 取得 8 個字元
for c in buffer:
# https://stackoverflow.com/questions/19897209/troubleshooting-typeerror-ord-expected-string-of-length-1-but-int-found
# if ord(c) > 0:
if c > 0:
# 40 is carriage return which signifies
# we are done looking for characters
# 40 = Enter
if int(c) == 40:
done = True
break;
# If we are shifted then we have to
# use the hid2 characters.
if shift:
# If it is a '2' then it is the shift key
if int(c) == 2:
shift = True
# if not a 2 then lookup the mapping
else:
str += hid2[int(c)]
shift = False
# If we are not shifted then use
# the hid characters
else:
# If it is a '2' then it is the shift key
if int(c) == 2:
shift = True
# if not a 2 then lookup the mapping
else:
str += hid[int(c)]
print(str)
if __name__ == '__main__':
try:
while True:
barcode_reader()
except KeyboardInterrupt:
pass
參考
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